$futureDate=date(“Y-m-d”, strtotime(“+one year”, $startDate));It”s returning the wrong date. Any ideas why?
abatishchev
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asked Dec 15, 2009 at3:48
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$futureDate=date(“Y-m-d”, strtotime(“+1 year”));$futureDate is one year from now!
$futureDate=date(“Y-m-d”, strtotime(“+1 year”, strtotime($startDate)) );$futureDate is one year from $startDate!
answered Jan 25, 2013 at 15:17
MishoMisho
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To add one year to todays date use the following:
$oneYearOn = date(“Y-m-d”,strtotime(date(“Y-m-d”, mktime()) . ” + 365 day”));For the other examples you must initialize $StartingDate with a timestamp value forexample:
$StartingDate = mktime(); // todays date as a timestampTry this
$newEndingDate = date(“Y-m-d”, strtotime(date(“Y-m-d”, strtotime($StaringDate)) . ” + 365 day”));or
$newEndingDate = date(“Y-m-d”, strtotime(date(“Y-m-d”, strtotime($StaringDate)) . ” + 1 year”));
abatishchev
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answered Dec 15, 2009 at 9:09
Nidhin BabyNidhin Baby
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//1 year from today”s dateecho date(“d-m-Y”, strtotime(“+1 year”));//1 year from from specific dateecho date(“22-09-Y”, strtotime(“+1 year”));hope this simpler bit of code helps someone in future 🙂
answered Jul 31, 2017 at 15:26
Đang xem: Get year from date php
DeveloperDeveloper
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Try: $futureDate=date(“Y-m-d”,strtotime(“+1 year”,$startDate));
answered Dec 15, 2009 at 3:52
K PrimeK Prime
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just had the same problem, however this was the simplest solution:
answered Mar 29, 2013 at 9:18
GardeneeGardenee
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// Declare a variable for this year $this_year = date(“Y”);// Add 1 to the variable$next_year = $this_year + 1;$year_after = $this_year + 2;// Check your code echo “This year is “; echo $this_year; echo “”; echo “Next year is “; echo $next_year; echo “”; echo “The year after that is “; echo $year_after;
answered Jan 6, 2016 at 23:59
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I prefer the OO approach:
$date = new DateTimeImmutable(“today”); //”today” gives midnight, leave blank for current time.$futureDate = $date->add(DateInterval::createFromDateString(“+1 Year”))Use DateTimeImmutable otherwise you will modify the original date too! more on DateTimeImmutable: http://php.net/manual/en/class.datetimeimmutable.php
If you just want from todays date then you can always do:
new DateTimeImmutable(“-1 Month”);
answered Dec 14, 2016 at 17:06
Andrew AtkinsonAndrew Atkinson
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If you are using PHP 5.3, it is because you need to set the default time zone:
date_default_timezone_set()
answered Dec 15, 2009 at 3:55
SeanJASeanJA
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strtotime() is returning bool(false), because it can”t parse the string “+one year” (it doesn”t understand “one”). false is then being implicitly cast to the integer timestamp 0. It”s a good idea toverify strtotime()”s output isn”t bool(false) before you go shoving it in other functions.
From the docs:
Return Values
Returns a timestamp on success, FALSE otherwise. Previous to PHP 5.1.0, this function would return -1 on failure.
answered Dec 15, 2009 at 4:00
Frank FarmerFrank Farmer
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Try This
$nextyear = date(“M d,Y”,mktime(0, 0, 0, date(“m”,strtotime($startDate)), date(“d”,strtotime($startDate)), date(“Y”,strtotime($startDate))+1));
answered Dec 15, 2009 at 3:56
TrebyTreby
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There is also a simpler and less sophisticated solution:
$monthDay = date(“m/d”);$year = date(“Y”)+1;$oneYearFuture = “”.$monthDay.”/”.$year.””;echo”The date one year in the future is: “.$oneYearFuture.””;
answered Jun 16, 2013 at 4:59
Daniel LimaDaniel Lima
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My solution is: date(“Y-m-d”, time()-60*60*24*365);
You can makeit more “readable” with defines:
define(“ONE_SECOND”, 1);define(“ONE_MINUTE”, 60 * ONE_SECOND);define(“ONE_HOUR”, 60 * ONE_MINUTE);define(“ONE_DAY”, 24 * ONE_HOUR);define(“ONE_YEAR”, 365 * ONE_DAY);date(“Y-m-d”, time()-ONE_YEAR);
answered May 22, 2020 at 13:41
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You can use strtotime() to get future time.
//strtotime(“+1 day”);//strtotime(“+1 week”);//strtotime(“+1 month”); $now = date(“Y-m-d”); $oneYearLaterFromNow = date(“Y-m-d”, strtotime(“+1 year”)); $oneYearLaterFromAnyDate = date(“Y-m-d”, strtotime(“+1 year”, strtotime($anyValidDateString)));
answered Oct 28, 2021 at 11:05
infomasudinfomasud
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In my case (i want to add 3 years to current date) the solution was:
$future_date = date(“Y-m-d”, strtotime(“now + 3 years”));To Gardenee, Treby and Daniel Lima: what will happen with 29th February? Sometimes February has only 28 days 🙂