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Trang chủ mysql count

MYSQL COUNT

by Admin _ April 26, 2022

$result = mysql_query("SELECT COUNT(*) FROM Students;");I need the result to display. But I am not getting the result.

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I have tried with the following methods:

mysql_fetch_assoc()mysql_free_result()mysql_fetch_row()

But I didn"t succeed khổng lồ display (get) the actual value.


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You need to alias the aggregate using the as từ khoá in order to gọi it from mysql_fetch_assoc

$result=mysql_query("SELECT count(*) as total from Students");$data=mysql_fetch_assoc($result);echo $data<"total">;

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here is the code for showing no of rows in the table with PHP

$sql="select count(*) as total from student_table";$result=mysqli_query($con,$sql);$data=mysqli_fetch_assoc($result);echo $data<"total">;

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With mysql v5.7.20, here is how I was able lớn get the row count from a table using PHP v7.0.22:

$query = "select count(*) from bigtable";$qresult = mysqli_query($this->conn, $query);$row = mysqli_fetch_assoc($qresult);$count = $row<"count(*)">;echo $count;The third line will return a structure that looks like this:

array(1) <"count(*)">=>string(4) "1570"In which case the ending echo statement will return:

1570
If you only need the value:

$result = mysql_query("SELECT count(*) from Students;");echo mysql_result($result, 0);
You can as well use this and upgrade to mysqli_ (stop using mysql_* extension...)

$result = mysqli_query($conn, "SELECT COUNT(*) AS `count` FROM `Students`");$row = mysqli_fetch_array($result);$count = $row<"count">;echo $count;
Please start using PDO.

mysql_* is deprecated as of PHP 5.5.0 và will be removed entirely in 7. Let"s make it easier to lớn upgrade & start using it now.

$dbh = new PDO($dsn, $user, $password);$sth = $dbh->prepare("SELECT count(*) as total from Students");$sth->execute();print_r($sth->fetchColumn());
For mysqli users, the code will look like this:

$mysqli = new mysqli($db_host, $db_user, $db_pass, $db_name);$result = $mysqli->query("SELECT COUNT(*) AS Students_count FROM Students")->fetch_array();var_dump($result<"Students_count">);or:

$mysqli = new mysqli($db_host, $db_user, $db_pass, $db_name);$result = $mysqli->query("SELECT COUNT(*) FROM Students")->fetch_array();var_dump($result<0>);
$result = mysql_query("SELECT COUNT(*) AS `count` FROM `Students`");$row = mysql_fetch_assoc($result);$count = $row<"count">;Try this code.


$num_result = mysql_query("SELECT count(*) as total_count from Students ") or exit(mysql_error());$row = mysql_fetch_object($num_result);echo $row->total_count;
$db = new PDO("mysql:host=localhost;dbname=java_db", "root", "pass");$Sql = "SELECT count(*) as `total` FROM users";$stmt = $db->query($Sql);$stmt->execute();$total = $stmt->fetch(PDO::FETCH_ASSOC);print "";print_r($total);print "";Result:

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You need to alias the aggregate using the as từ khoá in order to điện thoại tư vấn it from mysqli_fetch_assoc

$result=mysqli_query($conn,"SELECT count(*) as total from Students");$data=mysqli_fetch_assoc($result);echo $data<"total">;
$howmanyuser_query=$conn->query("SELECT COUNT(uno) FROM userentry;"); $howmanyuser=$howmanyuser_query->fetch_array(MYSQLI_NUM); echo $howmanyuser<0>;after the so many hours excellent :)


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